Thomas calculus instructor's solutions manual

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A template showing an example of the CAS commands needed to execute the solution is provided for each exercise type. (b) i) The given equation is equivalent to y = — 2x 4.

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Instructor's Solutions Manual Parti to accompany Thomas' Calculus Tenth Editon Instructor's Solutions Manual Parti John L. Weir Naval Postgraduate School to accompany Thomas 5 Calculus Tenth Edition Based on the orinal work by George B. Massachusetts Institute of Technology As revised by Ross L. No part of this publication may be reproduced, stored in a retrieval system, or transmitted in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without the prior written permission of the publisher. ISBN 0-321- 19778-X 12 3 4 5 6 CRS 06 05 04 03 PEARSON Addison Wesley PREFACE TO THE INSTRUCTOR This Instructor's Solutions Manual contains the solutions to every exercise in the 10th Edition of Thomas' CALCULUS as revised by Ross L. In addition to including the solutions to all of the new exercises in this edition of Thomas' CALCULUS, we have carefully reviewed every solution which appeared in previous solutions manuals to ensure that each solution • conforms exactly to the methods, procedures and steps presented in the text • is mathematiy correct • includes all of the steps necessary so a typical calculus student can follow the logical argument and algebra • includes a graph or fure whenever ed for by the exercise or, if needed, to help with the explanation • is formatted in an appropriate style to aid in its understanding Every CAS exercise is solved in both the MAPLE and MATHEMATICA computer algebra systems. ii) The desired line has slope ^4-= 1 and passes through (0,0): y = l(x — 0) or y=x.

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Similar exercises within the text ing require a change only in the input function or other numerical input parameters associated with the problem (such as the interval endpoints or the number of iterations). The desired line has slope —2 and passes through (-2,2):y = -2(x 2) 2 or y = -2x-2. (a) The given equations are equivalent to y = -|x r and y = — x 1, respectively, so the slopes are 2_ and — 1. 69 ; 5 = =££ = -3.75 degrees/inch 0.4-0 0.4 ( b ) m * 4°r~ 6 4 = y^ « -16.1 degrees/inch ( c ) m * fell = ff - - 7 - 1 Agrees/inch (d) Best insulator: Fiberglass insulation Poorest insulator: Gypsum wallboard The best insulator will have the largest temperature change per inch, because that will allow larger temperature differences on opposite sides of thinner layers. Slope: k = -^§ = ^•^_~ 1 = ~|p = 0.0994 atmospheres per meter At 50 meters, the pressure is p = 0,0994(50) 1 = 5.97 atmospheres. 2 Functions and Graphs 15 (c) g = g(h(x)) (d)y = f(f(x)) (f) y = g(f(h(x))) 43. v °' v ' g(x) g(x) ' ev ; X - 1 (c) Since (fog)(x)=f(l) = x,f(x)=i (d) Since (f o g)(x) = f ( v^) = | x |, f(x) = x 2 .

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